JPexamの商品はIT業界の専門家が自分の豊かな知識と経験を利用して認証試験に対して研究出たので品質がいいの試験の資料でございます。受験者がJPexamを選択したら高度専門の試験に１００％合格することが問題にならないと保証いたします。
JPexamのOracleの1Z0-805試験トレーニング資料は全てのオンラインのトレーニング資料で一番よいものです。我々の知名度はとても高いです。これは受験生の皆さんが資料を利用した後の結果です。JPexamのOracleの1Z0-805試験トレーニング資料を選んだら、１００パーセントの成功率を保証します。もし失敗だったら、我々は全額で返金します。受験生の皆さんの重要な利益が保障できるようにJPexamは絶対信頼できるものです。
JPexamがもっと早くOracleの1Z0-805認証試験に合格させるサイトで、Oracleの1Z0-805認証試験についての問題集が市場にどんどん湧いてきます。あなたがまだ専門知識と情報技術を証明しています強い人材で、JPexamのOracleの1Z0-805認定試験について最新の試験問題集が君にもっとも助けていますよ。
JPexamは受験者に向かって試験について問題を解決する受験資源を提供するサービスのサイトで、さまざまな受験生によって別のトレーニングコースを提供いたします。受験者はJPexamを通って順調に試験に合格する人がとても多くなのでJPexamがIT業界の中で高い名声を得ました。
試験番号：1Z0-805問題集
試験科目：Upgrade to Java SE 7 Programmer
最近更新時間：2013-12-28
問題と解答：全90問
100％の返金保証。1年間の無料アップデート。
JPexamは優れたIT情報のソースを提供するサイトです。JPexamで、あなたの試験のためのテクニックと勉強資料を見つけることができます。JPexamのOracleの1Z0-805試験トレーニング資料は豊富な知識と経験を持っているIT専門家に研究された成果で、正確度がとても高いです。JPexamに会ったら、最高のトレーニング資料を見つけました。JPexamのOracleの1Z0-805試験トレーニング資料を持っていたら、試験に対する充分の準備がありますから、安心に利用したください。
購入前にお試し,私たちの試験の質問と回答のいずれかの無料サンプルをダウンロード：http://www.jpexam.com/1Z0-805_exam.html
NO.1 Given the code fragment:
List<Person> pList = new CopyOnWriteArrayList<Person>();
Which statement is true?
A. Read access to the List should be synchronized.
B. Write access to the List should be synchronized.
C. Person objects retrieved from the List are thread-safe.
D. A Person object retrieved from the List is copied when written to.
E. Multiple threads can safely delete Person objects from the List.
Answer: C
Oracle 1Z0-805練習問題 1Z0-805練習問題
NO.2 Given the code fragment: public class Test {
public static void main (String [] args) {
Path path1 = Paths.get("D:\\sys\\asm\\.\\data\\..\\..\\mfg\\production.log");
System.out.println(path1.normalize());
System.out.println(path1.getNameCount());
}
}
What is the result?
A. D:\sys\mfg\production.log 8
B. D:\\sys\\asm\\.\\data\\. . \\mfg\\production.log 6
C. D: \\sys\\asm\\.\\data\\. . \\mfg\\production.log 8
D. D: \sys\mfg\production.log 4
E. D: \\ sys\\asm\\data\\mfg\\production.log 6
Answer: A
Oracle 1Z0-805 1Z0-805参考書
NO.3 Given the following code fragment:
public class Calc {
public static void main (String [] args) {
//* insert code here Line ** System.out.print("The decimal value is" + var);
}
}
Which three code fragments, when inserted independently at line **, enable the code to compile/
A. int var = 0b_1001;
B. long var = 0b100_01L;
C. float var = 0b10_01;
D. float var = 0b10_01F;
E. double var = 0b10_01;
F. double var = 0b10_01D;
Answer: B,C,E
Oracle 1Z0-805 1Z0-805認定証 1Z0-805 1Z0-805 1Z0-805認証試験
NO.4 Which code fragments print 1?
A. String arr [] = {"1", "2", "3"}; List <? extendsString > arrList = new LinkedList <> (Arrays.asList (arr));
System.out.println (arrList.get (0));
B. String arr [] = {"1", "2", "3"}; List <Integer> arrList = new LinkedList <> (Arrays.asList (arr));
System.out.println (arrList.get (0));
C. String arr [] = {"1", "2", "3"}; List <?> arrList = new LinkedList <> (Arrays.asList (arr)); System.out.println
(arrList.get (0));
D. String arr [] = {"1","2","3"}; List <?> arrList = new LinkedList <?>(Arrays.asList (arr)); System.out.println
(arrList.get (0));
E. String arr [] = {"1","2","3"}; List <Integer> extendsString > arrList =new LinkedList <Integer>
(Arrays.asList (arr)); System.out.println (arrList.get (0));
Answer: A,C
Oracle練習問題 1Z0-805 1Z0-805 1Z0-805
NO.5 Given the code fragment:
public static void main(String[] args) {
String source = "d:\\company\\info.txt";
String dest = "d:\\company\\emp\\info.txt";
//insert code fragment here Line **
} catch (IOException e) {
System.err.println ("Caught IOException: " + e.getmessage();
}
}
Which two try statements, when inserted at line **, enable the code to successfully move the file info.txt to
the destination directory, even if a file by the same name already exists in the destination directory?
A. try {FileChannel in = new FileInputStream(source).getChannel(); FileChannel out = new
FileOutputStream(dest).getChannel (); in.transferTo (0, in.size(), out);
B. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
C. try {Files.copy(Paths.get(source), Paths.get(dest)); Files.delete(Paths.get(source));
D. try {Files.move(Paths.get(source),Paths.get(dest));
E. try {BufferedReader br = Files.newBufferedReader(Paths.get(source), Charset.forName ("UTF8"));
BufferedWriter bw = Files.newBufferedWriter (Paths.get(dest), Charset.forName ("UTF-8")); String record
= ""; while ((record = br.readLine()) != null){ bw.write (record); bw.newLine(); }
Files.delete(Paths.get(source));
Answer: B,D
Oracle 1Z0-805 1Z0-805認証試験
NO.6 Which statement is true about the take method defined in the WatchService interface?
A. Retrieves and removes the next watch key, or returns null of none are present.
B. Retrieves and removes the next watch key. If a queued key is not immediately available, the program
waits for the specified wait time.
C. Retrieves and removes the next watch key: waits if no key is yet present.
D. Retrieves and removes all pending events for the watch key, returning a list of the events that were
retrieved.
Answer: C
Oracle認証試験 1Z0-805問題集 1Z0-805問題集 1Z0-805問題集 1Z0-805認定資格
NO.7 Given the fragment:
public class CustomerApplication {
public static void main (String [] args) {
CustomerDAO custDao = new CustomerDAOMemoryImp1 ();
// . . . other methods
} }
Which two valid alternatives to line 3 would decouple this application from a specific implementation of
customerDAO?
A. CustomerDAO custDao = new customerDAO();
B. CustomerDAO custDao = (CustomerDAO) new object();
C. CustomerDAO custDao = CustomerDAO.getInstance();
D. CustomerDAO custDao = (CustomerDAO) new CustomerDAOmemoryImp1();
E. CustomerDAO custDao = CustomerDAOFactory.getInstance();
Answer: C,E
Oracle 1Z0-805 1Z0-805 1Z0-805 1Z0-805問題集
NO.8 Given:
import java.util.*; public class StringApp { public static void main (String [] args) { Set <String> set = new
TreeSet <> (); set.add("X"); set.add("Y"); set.add("X"); set.add("Y"); set.add("X"); Iterator <String> it =
set.iterator (); int count = 0; while (it.hasNext()) { switch (it.next()){ case "X": System.out.print("X "); break;
case "Y": System.out.print("Y "); break; } count++; } System.out.println ("\ncount = " + count); } }
What is the result?
A. X X Y X Y count = 5
B. X Y X Y count = 4
C. X Y count = s
D. X Y count = 2
Answer: D
Oracle 1Z0-805過去問 1Z0-805認定証 1Z0-805過去問 1Z0-805認定証 1Z0-805練習問題
NO.9 You are using a database from XY/Data. What is a prerequisite for connecting to the database using a
JDBC 4.0 driver from XY/Data?
A. Use the JDBC DriverManager.loadDriver method.
B. Put the XY/data driver into the classpath of your application.
C. Create an instance of the XY/Data driver class using the new keyword.
D. Create an Implementation of DriverManager that extends the XY/Data driver
Answer: B
Oracle 1Z0-805 1Z0-805過去問 1Z0-805参考書
NO.10 Which two statements are true about the walkFileTree method of the files class?
A. The file tree traversal is breadth-first with the given FileVisitor invoked for each file encountered.
B. If the file is a directory, and if that directory could not be opened, the postVisitFileFailed method is
invoked with the I/O exception.
C. The maxDepth parameter s value is the maximum number of directories to visit.
D. By default, symbolic links are not automatically followed by the method.
Answer: C,D
Oracle 1Z0-805練習問題 1Z0-805 1Z0-805問題集 1Z0-805練習問題 1Z0-805認定資格
NO.11 Given the code fragment:
private static void copyContents (File source, File target) {
try {inputStream fis = new FileInputStream(source);
outputStream fos = new FileOutputStream (target);
byte [] buf = new byte [8192]; int i;
while ((i = fis.read(buf)) != -1) {
fos.write (buf, 0, i);
}
//insert code fragment here. Line **
System.out.println ("Successfully copied");
}
Which code fragments, when inserted independently at line **, enable the code to compile?
A. }catch (IOException | NoSuchFileException e) { System.out.println(e); }
B. } catch (IOException | IndexOutOfBoundException e) { System.out.println(e); }
C. } catch (Exception | IOException | FileNotFoundException e ) { System.out.println(e); }
D. } catch (NoSuchFileException e ) { System.out.println(e); }
E. } catch (InvalidPathException | IOException e) { System.out.println(e); }
Answer: B,D,E
Oracle認定試験 1Z0-805 1Z0-805 1Z0-805 1Z0-805
NO.12 Given three resource bundles with these values set for menu1: ( The default resource bundle is
written in US English.)
English US resource Bundle Menu1 = small
French resource Bundle Menu1 = petit
Chinese Resource Bundle Menu = 1
And given the code fragment:
Locale.setDefault (new Locale("es", "ES")); // Set default to Spanish and Spain loc1 = Locale.getDefault();
ResourceBundle messages = ResourceBundle.getBundle ("messageBundle", loc1); System.out.println
(messages.getString("menu1")); What is the result?
A. No message is printed
B. petit
C. :
D. Small
E. A runtime error is produced
Answer: E
Oracle参考書 1Z0-805練習問題 1Z0-805 1Z0-805過去問 1Z0-805
NO.13 Given a resource bundle MessageBundle, what is the name of the default bundle file?
A. MessageBundle.profile
B. MessageBundle.xml
C. MessageBundle.java
D. MessageBundle.properties
Answer: D
Oracle認定資格 1Z0-805 1Z0-805練習問題
NO.14 Given the code fragment:
dataFormat df;
Which statement defines a new DataFormat object that displays the default date format for the UK
Locale?
A. df = DateFormat.getDateInstance (DateFormat.DEFAULT, Locale(UK));
B. df = DateFormat.getDateInstance (DateFormat.DEFAULT, UK);
C. df = DateFormat.getDateInstance (DateFormat.DEFAULT, Locale.UK);
D. df = new DateFormat.getDataInstance (DataFormat.DEFAULT, Locale.UK);
E. df = new DateFormat.getDateInstance (DateFormat.DEFAULT, Locale(UK));
Answer: C
Oracle 1Z0-805 1Z0-805過去問 1Z0-805練習問題 1Z0-805 1Z0-805
NO.15 What design pattern does the Drivermanager.getconnection () method characterize?
A. DAO
B. Factory
C. Singleton
D. composition
Answer: B
Oracle 1Z0-805認定試験 1Z0-805認定証
JPexamは最新のNS0-156問題集と高品質のHP2-E56問題と回答を提供します。JPexamの000-502 VCEテストエンジンとLOT-405試験ガイドはあなたが一回で試験に合格するのを助けることができます。高品質のSY0-301 PDFトレーニング教材は、あなたがより迅速かつ簡単に試験に合格することを100％保証します。試験に合格して認証資格を取るのはそのような簡単なことです。
没有评论:
发表评论